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30 changes: 30 additions & 0 deletions Programmers/Level1/12928_약수의_합.js
Original file line number Diff line number Diff line change
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/*
⭐️ 문제 정보 ⭐️
문제 : 12928 - 약수의 합
레벨 : Level 1
링크 : https://school.programmers.co.kr/learn/courses/30/lessons/12928
*/

// ANCHOR - 2026.01.20 풀이
/**
* NOTE
* 약수는 항상 쌍으로 존재하기 때문에 √n (i * i <= n) 까지만 탐색하면 된다는 점을 잊지 말기
*/
function getDivisors(n) {
const divisors = [];

for (let i = 1; i * i <= n; i++) {
if (n % i === 0) {
divisors.push(i);
if (n / i !== i) {
divisors.push(n / i);
}
}
}

return divisors;
}

function solution(n) {
return getDivisors(n).reduce((acc, cur) => acc + cur, 0);
}