Add support for multiple continuous input ports

[pnbabu]

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[github-actions]

Bencher Report

Branch	1218/merge
Testbed	ubuntu-latest

🚨 1 Alert

Iteration	Benchmark	Measure Units	View	Benchmark Result (Result Δ%)	Upper Boundary (Limit %)
0	tests/nest_continuous_benchmarking/test_nest_continuous_benchmarking.py::TestNESTContinuousBenchmarking::test_stdp_nn_synapse	Latency seconds (s)	📈 plot 🚷 threshold 🚨 alert (🔔)	4.01 s (+16.26%) Baseline: 3.45 s	3.79 s (105.69%)

Click to view all benchmark results

Benchmark	Latency	Benchmark Result seconds (s) (Result Δ%)	Upper Boundary seconds (s) (Limit %)
tests/nest_continuous_benchmarking/test_nest_continuous_benchmarking.py::TestNESTContinuousBenchmarking::test_stdp_nn_synapse	📈 view plot 🚷 view threshold 🚨 view alert (🔔)	4.01 s (+16.26%) Baseline: 3.45 s	3.79 s (105.69%)

Benchmark	Latency	Benchmark Result seconds (s) (Result Δ%)	Upper Boundary seconds (s) (Limit %)
tests/nest_continuous_benchmarking/test_nest_continuous_benchmarking.py::TestNESTContinuousBenchmarking::test_stdp_nn_synapse	📈 view plot 🚷 view threshold 🚨 view alert (🔔)	3.37 s (-1.88%) Baseline: 3.44 s	3.78 s (89.20%)

Benchmark	Latency	Benchmark Result seconds (s) (Result Δ%)	Upper Boundary seconds (s) (Limit %)
tests/nest_continuous_benchmarking/test_nest_continuous_benchmarking.py::TestNESTContinuousBenchmarking::test_stdp_nn_synapse	📈 view plot 🚷 view threshold 🚨 view alert (🔔)	3.42 s (-0.69%) Baseline: 3.44 s	3.79 s (90.28%)

🐰 View full continuous benchmarking report in Bencher

[clinssen]

Can these values be derived from the number of steps taken and DC amplitudes? By that token, why is this value 2370 and not 3000?

[pnbabu]

It's not the direct addition of the current, but a cumulative sum divided by conductance V_m1 += I_1 / 5 nS.

[clinssen]

The input is 150 and the script simulates for 10 ms at 0.1 ms resolution, so a total of 100 timesteps. There is a factor 1/5 in the script, so the total should be 150*100/3 = 3000, not 2370, right? Can you explain where the value 2370 comes from?

[pnbabu]

We should also take delay into consideration, which is 1 ms by default (10 timesteps), and we add the external current at the end of the update() function, i.e., after all the update statements are executed. Also, the multimeter records 90 values, which I think is due to the min_delay. Taking all these into consideration, the final value of V_m = (90-11)*150/5 = 2370.