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Check out this pull request on  ReviewNB

See visual diffs & provide feedback on Jupyter Notebooks.


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@dealmeidavf dealmeidavf left a comment

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Please see my comments (see below) about typesetting in the report changes you made. If this is what you really want, let me know and I will merge into the main branch.

"\\begin{align*}\n",
" -\\frac{1}{r^2}\\bigl(-D_1\\, r^2 u_1'\\bigr)'(r) - \\Sigma_{a,1}\\,u_1(r) + s_{0,1} &= 0 \\quad\\quad \\forall \\quad\\quad r\\in\\ ]0,R[, \\\\\n",
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Eliminating the small space makes the equation look odd since the diffusion coefficient shows up too close to the unknown variable. Proper typesetting calls for a small space to make the distinction. Note the difference $D_1\,r^2 u_1$ and $D_1r^2u_1$. The former is better.

@@ -179,13 +180,13 @@
"\n",
"\\begin{align*}\n",
"y = c_1 e^{m_1x} + c_2 e^{m_2 x} \n",
" + \\frac{e^{m_1x}}{m_1-m_2} \\int R\\left(x\\right) e^{-m_1x} \\, dx\n",
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@dealmeidavf dealmeidavf Dec 19, 2024

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The integrand and the differential should be separated by a space: $\int x dx$ and $\int x\,dx$. Latter is better and you will see in calculus books.

"\\end{align*}\n",
"\n",
"where $a$ and $b$ are constants, and $m_1$ and $m_2$ are the real and distinct roots of $m^2+am+b=0$.\n",
"\n",
"Thus, for $w_i=r\\,u_i$, $a=0$, $b=-\\frac{\\Sigma_{a,i}}{D_i}$, $R=- r\\frac{s_{0,i}}{D_i}$, and the roots are\n",
"Thus, for $w_i=r u_i$, $a=0$, $b=-\\frac{\\Sigma_{a,i}}{D_i}$, $R=- r\\frac{s_{0,i}}{D_i}$, and the roots are\n",
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@dealmeidavf dealmeidavf Dec 19, 2024

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What you proposing: $w_i=r u_i$ does not look better than $w_i=r\,u_i$. Separate the unknown from the surrounding constants or independent variable. Similar comments to all other changes you made eliminating the small space in LaTeX.

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3 participants