syntax error: bad arithmetic expression, unexpected token `@`.

[willstore69]

i got error

new-menu.sh(54:37): syntax error: bad arithmetic expression, unexpected token @.

[willstore69]

to produce this issue

try use

if (( $var == "@" )); then

[yassinebenaid]

I think your syntax is incorrect. Instead of

- if (( $var  == "@" ));
+ if [[ $var  = "@" ]];

This is because the parentheses mean a different thing when used in if conditions. They expect 3 arithmetic expresssions seperated by semicolons. Just like in C or PHP.

This is not specific to bunster by the way, it is just how bash works.

[cswingler]

What dialect of shell script is this project targeting? That's a valid construct in bash--but only for arithmetic: https://tldp.org/LDP/abs/html/dblparens.html

bash-5.3$ if (( 1 == 1)); then echo "yup"; fi
yup
bash-5.3$ if (( 1 ==  2 )); then echo "yup"; fi
bash-5.3$

# This does not work as expected a single string is coerced to an integer of 1:
bash-5.3$ var="thing"
bash-5.3$ if (( "$var" ==  "thing" )); then echo "yup"; fi
yup
bash-5.3$ if (( "$var" ==  "nothing" )); then echo "yup"; fi
yup
# and putting a space into it effectively turns it into an array:
bash-5.3$ if (( "$var" ==  "not thing" )); then echo "yup"; fi
bash: ((: thing ==  not thing : arithmetic syntax error in expression (error token is "thing ")

bash-5.3$ var="other thing"
bash-5.3$ if (( "$var" ==  "nothing" )); then echo "yup"; fi
bash: ((: other thing ==  nothing : arithmetic syntax error in expression (error token is "thing ==  nothing ")

C-style trinaries are supported, but double-parens doesn't imply that it's immediately a trinary.

Given that, this is still an example of bad syntax. @ is a reserved character that requires some special handling, even in bash: https://askubuntu.com/questions/544545/bash-script-to-check-if-input-has-an