Is the delete/update operation synchronized blocking?

[ZJRui]

A_Clipboard := ""
Send "{Shift down}{Right}{Shift up}{Ctrl down}c{Ctrl up}{Left}"   ---> copy "abc"
ClipWait(0.5)


ClipboardHistory.DeleteItem(2) 


A_Clipboard := ""
Send "{Ctrl down}{Left}{Shift down}{Right}{Shift up}c{Ctrl up}{Right}"  copy "def"
ClipWait(0.5)

Is the delete operation synchronized blocking? I need him to block it synchronously. The code above must be deleted ABC? Is it possible to delete the latest "BDG"?

[ZJRui]

I tried it not synchronized. He deleted my useful historical data and did not delete the latest CTRL+C data.

[ZJRui]

Capslock & q:: {
    A_Clipboard := ""
    Send "{Shift down}{Right}{Shift up}{Ctrl down}c{Ctrl up}{Left}"
    ClipWait(0.5)
    ; MsgBox("copy content<" . SubStr(A_Clipboard, -1, 1) . ">")
    if (str := SubStr(A_Clipboard, -1, 1)) {
        /**
         * 删除历史记录中的第一个
         */
        if (ClipboardHistory.Count > 0) {
            ; MsgBox("delete empty item<" . ClipboardHistory.GetText(1) . ">")
            ClipboardHistory.DeleteItem(2)
        }
        if (str = " ") {
            ;向左复制
            A_Clipboard := ""
            Send "{Ctrl down}{Left}{Shift down}{Right}{Shift up}c{Ctrl up}{Right}"
            ClipWait(0.5)
        } else if (InStr(str, "`n") || InStr(str, "`r")) {
            A_Clipboard := ""
            ;shift+right 向右复制的是回车换行.通常在发生在光标在行末的时候,此时需要shift+left向左复制 判断左边是否有单词
            Send "{Ctrl down}{Left}{Shift down}{Right}{Shift up}c{Ctrl up}{Right}"
            ClipWait(0.5)
        }
        else if (StrLen(str) = 0) {
            ;系统剪贴板为空,且脚本刚加载,此时A_Clipboard就是空.
            MsgBox("empty str ,len=0")
            return
        } else {
            ;向右复制到一个字后 开始跳转到左边复制整个单词. 注意此时单词的复制末尾可能包含空格,也就是编辑器将空格作为了单词的一部分
            A_Clipboard := ""
            Send "{Ctrl down}{Right}{Left}{Shift down}{Right}{Shift up}c{Ctrl up}{Right}"
            ClipWait(0.5)
        }
    } else {
        return ;
    }
    ;The trailing space of the word is copied in notepad
    trimmedClipboard := Trim(A_Clipboard)
    /**
     * \r：代表回车（Carriage Return），ASCII 码为 13（十进制）或 0D（十六进制）。
     * \n：代表换行（Line Feed），ASCII 码为 10（十进制）或 0A（十六进制）。
     */
    trimmedClipboard := LTrim(trimmedClipboard, "`r`n")
    ; MsgBox("copy content length    " . StrLen(trimmedClipboard) "     content<" . trimmedClipboard . ">")
    if (StrLen(trimmedClipboard) == 0) {
        if (ClipboardHistory.Count > 0) {
            ; MsgBox("delete empty item<" . ClipboardHistory.GetText(1) . ">")
            ClipboardHistory.DeleteItem(2)
        }
    }
}

The function of this code is to copy the entire word near the input cursor.

1. Because the code is determined by copying a character to the right to go left or right to the right, you need to delete this record in the historical record

2. Considering the content that may be copied to blank, you need to delete the latest blank records

[ZJRui]

If you cancel MSGBOX notes, the code can run normally. If the MGSBOX annotation code is closed, there is a bug, I guess the reason is that delete is not a synchronous operation.