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MinCostToConnectAllPoints.java
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79 lines (64 loc) · 2.28 KB
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package graph;
import java.util.ArrayList;
import java.util.Comparator;
import java.util.List;
/**
* Description: https://leetcode.com/problems/min-cost-to-connect-all-points
* Difficulty: Medium
* Time complexity: O(n^2 * log n^2)
* Space complexity: O(n^2)
*/
public class MinCostToConnectAllPoints {
public int minCostConnectPointsViaUnionFind(int[][] points) {
int[] parents = new int[points.length];
int[] ranks = new int[points.length];
for (int i = 0; i < points.length; i++) {
parents[i] = i;
ranks[i] = 1;
}
List<Edge> edges = buildAllPossibleEdgesSortedByDistance(points);
int usedEdges = 0;
int cost = 0;
for (Edge edge : edges) {
if (unite(parents, ranks, edge.point1, edge.point2)) {
cost += edge.distance;
usedEdges++;
}
// all points are now connected
if (usedEdges == points.length - 1) break;
}
return cost;
}
private List<Edge> buildAllPossibleEdgesSortedByDistance(int[][] points) {
List<Edge> edges = new ArrayList<>();
for (int i = 0; i < points.length; i++) {
for (int j = i + 1; j < points.length; j++) {
int distance = Math.abs(points[i][0] - points[j][0]) + Math.abs(points[i][1] - points[j][1]);
edges.add(new Edge(i, j, distance));
}
}
edges.sort(Comparator.comparingInt(e -> e.distance));
return edges;
}
private boolean unite(int[] parents, int[] ranks, int node1, int node2) {
int parent1 = findParent(parents, node1);
int parent2 = findParent(parents, node2);
if (parent1 == parent2) return false;
if (ranks[parent1] > ranks[parent2]) {
parents[parent2] = parent1;
ranks[parent1] += ranks[parent2];
} else {
parents[parent1] = parent2;
ranks[parent2] += ranks[parent1];
}
return true;
}
private int findParent(int[] parents, int node) {
while (node != parents[node]) {
parents[node] = parents[parents[node]];
node = parents[node];
}
return node;
}
private record Edge(int point1, int point2, int distance) {}
}