Sync docs and metadata (#1024)

Author: BNAndras

exercises/practice/acronym/.docs/instructions.md

@@ -10,8 +10,8 @@ Punctuation is handled as follows: hyphens are word separators (like whitespace)
 
 For example:
 
-|Input|Output|
-|-|-|
-|As Soon As Possible|ASAP|
-|Liquid-crystal display|LCD|
-|Thank George It's Friday!|TGIF|
+| Input                     | Output |
+| ------------------------- | ------ |
+| As Soon As Possible       | ASAP   |
+| Liquid-crystal display    | LCD    |
+| Thank George It's Friday! | TGIF   |

exercises/practice/allergies/.docs/instructions.md

@@ -22,6 +22,6 @@ Now, given just that score of 34, your program should be able to say:
 - Whether Tom is allergic to any one of those allergens listed above.
 - All the allergens Tom is allergic to.
 
-Note: a given score may include allergens **not** listed above (i.e.  allergens that score 256, 512, 1024, etc.).
+Note: a given score may include allergens **not** listed above (i.e. allergens that score 256, 512, 1024, etc.).
 Your program should ignore those components of the score.
 For example, if the allergy score is 257, your program should only report the eggs (1) allergy.

exercises/practice/armstrong-numbers/.docs/instructions.md

@@ -5,9 +5,9 @@ An [Armstrong number][armstrong-number] is a number that is the sum of its own d
 For example:
 
 - 9 is an Armstrong number, because `9 = 9^1 = 9`
-- 10 is *not* an Armstrong number, because `10 != 1^2 + 0^2 = 1`
+- 10 is _not_ an Armstrong number, because `10 != 1^2 + 0^2 = 1`
 - 153 is an Armstrong number, because: `153 = 1^3 + 5^3 + 3^3 = 1 + 125 + 27 = 153`
-- 154 is *not* an Armstrong number, because: `154 != 1^3 + 5^3 + 4^3 = 1 + 125 + 64 = 190`
+- 154 is _not_ an Armstrong number, because: `154 != 1^3 + 5^3 + 4^3 = 1 + 125 + 64 = 190`
 
 Write some code to determine whether a number is an Armstrong number.
 

exercises/practice/atbash-cipher/.docs/instructions.md

@@ -1,6 +1,6 @@
 # Instructions
 
-Create an implementation of the atbash cipher, an ancient encryption system created in the Middle East.
+Create an implementation of the Atbash cipher, an ancient encryption system created in the Middle East.
 
 The Atbash cipher is a simple substitution cipher that relies on transposing all the letters in the alphabet such that the resulting alphabet is backwards.
 The first letter is replaced with the last letter, the second with the second-last, and so on.

exercises/practice/atbash-cipher/.meta/config.json

@@ -25,7 +25,7 @@
       ".meta/example.h"
     ]
   },
-  "blurb": "Create an implementation of the atbash cipher, an ancient encryption system created in the Middle East.",
+  "blurb": "Create an implementation of the Atbash cipher, an ancient encryption system created in the Middle East.",
   "source": "Wikipedia",
   "source_url": "https://en.wikipedia.org/wiki/Atbash"
 }

exercises/practice/binary-search-tree/.meta/config.json

@@ -24,6 +24,5 @@
     ]
   },
   "blurb": "Insert and search for numbers in a binary tree.",
-  "source": "Josh Cheek",
-  "source_url": "https://twitter.com/josh_cheek"
+  "source": "Josh Cheek"
 }

exercises/practice/binary-search/.docs/instructions.md

@@ -11,7 +11,7 @@ Binary search only works when a list has been sorted.
 
 The algorithm looks like this:
 
-- Find the middle element of a *sorted* list and compare it with the item we're looking for.
+- Find the middle element of a _sorted_ list and compare it with the item we're looking for.
 - If the middle element is our item, then we're done!
 - If the middle element is greater than our item, we can eliminate that element and all the elements **after** it.
 - If the middle element is less than our item, we can eliminate that element and all the elements **before** it.

exercises/practice/binary/.docs/instructions.md

@@ -20,7 +20,7 @@ A number 23 in base 10 notation can be understood as a linear combination of pow
 - The rightmost digit gets multiplied by 10^0 = 1
 - The next number gets multiplied by 10^1 = 10
 - ...
-- The *n*th number gets multiplied by 10^*(n-1)*.
+- The nth number gets multiplied by 10^_(n-1)_.
 - All these values are summed.
 
 So: `23 => 2*10^1 + 3*10^0 => 2*10 + 3*1 = 23 base 10`

exercises/practice/circular-buffer/.docs/instructions.md

@@ -4,39 +4,55 @@ A circular buffer, cyclic buffer or ring buffer is a data structure that uses a
 
 A circular buffer first starts empty and of some predefined length.
 For example, this is a 7-element buffer:
-<!-- prettier-ignore -->
-    [ ][ ][ ][ ][ ][ ][ ]
+
+```text
+[ ][ ][ ][ ][ ][ ][ ]
+```
 
 Assume that a 1 is written into the middle of the buffer (exact starting location does not matter in a circular buffer):
-<!-- prettier-ignore -->
-    [ ][ ][ ][1][ ][ ][ ]
+
+```text
+[ ][ ][ ][1][ ][ ][ ]
+```
 
 Then assume that two more elements are added — 2 & 3 — which get appended after the 1:
-<!-- prettier-ignore -->
-    [ ][ ][ ][1][2][3][ ]
+
+```text
+[ ][ ][ ][1][2][3][ ]
+```
 
 If two elements are then removed from the buffer, the oldest values inside the buffer are removed.
 The two elements removed, in this case, are 1 & 2, leaving the buffer with just a 3:
-<!-- prettier-ignore -->
-    [ ][ ][ ][ ][ ][3][ ]
+
+```text
+[ ][ ][ ][ ][ ][3][ ]
+```
 
 If the buffer has 7 elements then it is completely full:
-<!-- prettier-ignore -->
-    [5][6][7][8][9][3][4]
+
+```text
+[5][6][7][8][9][3][4]
+```
 
 When the buffer is full an error will be raised, alerting the client that further writes are blocked until a slot becomes free.
 
 When the buffer is full, the client can opt to overwrite the oldest data with a forced write.
 In this case, two more elements — A & B — are added and they overwrite the 3 & 4:
-<!-- prettier-ignore -->
-    [5][6][7][8][9][A][B]
+
+```text
+[5][6][7][8][9][A][B]
+```
 
 3 & 4 have been replaced by A & B making 5 now the oldest data in the buffer.
 Finally, if two elements are removed then what would be returned is 5 & 6 yielding the buffer:
-<!-- prettier-ignore -->
-    [ ][ ][7][8][9][A][B]
+
+```text
+[ ][ ][7][8][9][A][B]
+```
 
 Because there is space available, if the client again uses overwrite to store C & D then the space where 5 & 6 were stored previously will be used not the location of 7 & 8.
 7 is still the oldest element and the buffer is once again full.
-<!-- prettier-ignore -->
-    [C][D][7][8][9][A][B]
+
+```text
+[C][D][7][8][9][A][B]
+```

exercises/practice/clock/.meta/config.json

@@ -25,6 +25,5 @@
     ]
   },
   "blurb": "Implement a clock that handles times without dates.",
-  "source": "Pairing session with Erin Drummond",
-  "source_url": "https://twitter.com/ebdrummond"
+  "source": "Pairing session with Erin Drummond"
 }