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BestTimetoBuyandSellStockII.java
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47 lines (45 loc) · 1.61 KB
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package leetcode;
/**
* @author eko
* @date 2018/10/30 10:00 PM
*
* Say you have an array for which the ith element is the price of a given stock on day i.
*
* Design an algorithm to find the maximum profit. You may complete as many transactions as you like (i.e., buy one and sell one share of the stock multiple times).
*
* Note: You may not engage in multiple transactions at the same time (i.e., you must sell the stock before you buy again).
*
* Example 1:
*
* Input: [7,1,5,3,6,4]
* Output: 7
* Explanation: Buy on day 2 (price = 1) and sell on day 3 (price = 5), profit = 5-1 = 4.
* Then buy on day 4 (price = 3) and sell on day 5 (price = 6), profit = 6-3 = 3.
* Example 2:
*
* Input: [1,2,3,4,5]
* Output: 4
* Explanation: Buy on day 1 (price = 1) and sell on day 5 (price = 5), profit = 5-1 = 4.
* Note that you cannot buy on day 1, buy on day 2 and sell them later, as you are
* engaging multiple transactions at the same time. You must sell before buying again.
* Example 3:
*
* Input: [7,6,4,3,1]
* Output: 0
* Explanation: In this case, no transaction is done, i.e. max profit = 0.
*/
public class BestTimetoBuyandSellStockII {
public static void main(String[] args) {
int[] prices = {7,1,5,3,6,4};
int res = new BestTimetoBuyandSellStockII().maxProfit(prices);
System.out.println(res);
}
public int maxProfit(int[] prices) {
int profit = 0;
for (int i = 1; i < prices.length; i++) {
int incr = prices[i] - prices[i - 1];
if (incr > 0) profit += incr;
}
return profit;
}
}