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702.SearchinaSortedArrayofUnknownSize.h
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43 lines (30 loc) · 1.27 KB
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/*
Given an integer array sorted in ascending order, write a function to search target in nums. If target exists, then return its index, otherwise return -1. However, the array size is unknown to you. You may only access the array using an ArrayReader interface, where ArrayReader.get(k) returns the element of the array at index k (0-indexed).
You may assume all integers in the array are less than 10000, and if you access the array out of bounds, ArrayReader.get will return 2147483647.
Example 1:
Input: array = [-1,0,3,5,9,12], target = 9
Output: 4
Explanation: 9 exists in nums and its index is 4
Example 2:
Input: array = [-1,0,3,5,9,12], target = 2
Output: -1
Explanation: 2 does not exist in nums so return -1
Note:
You may assume that all elements in the array are unique.
The value of each element in the array will be in the range [-9999, 9999].
*/
int search(const ArrayReader& reader, int target) {
int l = 0, r = INT_MAX;
while (l < r) {
int m = l + (r-l)/2;
int x = reader.get(m);
if (x == target) {
return m;
} else if (x < target) {
l = m+1;
} else {
r = m;
}
}
return -1;
}