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461.HammingDistance.h
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60 lines (38 loc) · 1.01 KB
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/*
2016-12-24
bluepp
May the force be with me!
https://leetcode.com/problems/hamming-distance/
The Hamming distance between two integers is the number of positions at which the corresponding bits are different.
Given two integers x and y, calculate the Hamming distance.
Note:
0 ≤ x, y < 231.
Example:
Input: x = 1, y = 4
Output: 2
Explanation:
1 (0 0 0 1)
4 (0 1 0 0)
↑ ↑
The above arrows point to positions where the corresponding bits are different.
*/
/* 2018/11/01 */
int hammingDistance(int x, int y) {
int ret = 0;
for (int i = 0; i < 32; i++) {
int bit = 1 << i;
if ((x & bit) ^ (y & bit)) {
ret ++;
}
}
return ret;
}
int hammingDistance(int x, int y) {
int ret = 0;
int exc = x ^ y;
for (int i = 0; i < 32; i++)
{
ret += (exc >> i) & 1;
}
return ret;
}