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3SumClosest.h
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48 lines (38 loc) · 1.33 KB
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/* bleupp */
/* 2014-05-27 */
/* 2014-07-05 */
/* 2014-08-03 */
/* May the force be with me */
/*
Source: https://oj.leetcode.com/problems/3sum-closest/
Notes:
Given an array S of n integers, find three integers in S such that the sum is closest to
a given number, target. Return the sum of the three integers.
You may assume that each input would have exactly one solution.
For example, given array S = {-1 2 1 -4}, and target = 1.
The sum that is closest to the target is 2. (-1 + 2 + 1 = 2).
Solution: Similar to 3Sum, taking O(n^2) time complexity.
*/
int threeSumClosest(vector<int> &num, int target) {
int n = num.size();
sort(num.begin(), num.end());
int min_diff = INT_MAX; int res = INT_MAX;
for (int i = 0; i < n-2; i++)
{
int l = i+1, r = n-1;
while (l < r)
{
int tmp = num[i] + num[l] + num[r];
if (tmp == target) return target;
else if (tmp < target) l++;
else r--;
int diff = abs(target - tmp);
if (diff < min_diff)
{
min_diff = diff;
res = tmp;
}
}
}
return res;
}